3.11 \(\int \sqrt {\log (c (d+e x))} \, dx\)

Optimal. Leaf size=50 \[ \frac {(d+e x) \sqrt {\log (c (d+e x))}}{e}-\frac {\sqrt {\pi } \text {erfi}\left (\sqrt {\log (c (d+e x))}\right )}{2 c e} \]

[Out]

-1/2*erfi(ln(c*(e*x+d))^(1/2))*Pi^(1/2)/c/e+(e*x+d)*ln(c*(e*x+d))^(1/2)/e

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Rubi [A]  time = 0.03, antiderivative size = 50, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 5, integrand size = 12, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {2389, 2296, 2299, 2180, 2204} \[ \frac {(d+e x) \sqrt {\log (c (d+e x))}}{e}-\frac {\sqrt {\pi } \text {Erfi}\left (\sqrt {\log (c (d+e x))}\right )}{2 c e} \]

Antiderivative was successfully verified.

[In]

Int[Sqrt[Log[c*(d + e*x)]],x]

[Out]

-(Sqrt[Pi]*Erfi[Sqrt[Log[c*(d + e*x)]]])/(2*c*e) + ((d + e*x)*Sqrt[Log[c*(d + e*x)]])/e

Rule 2180

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))/Sqrt[(c_.) + (d_.)*(x_)], x_Symbol] :> Dist[2/d, Subst[Int[F^(g*(e - (c*
f)/d) + (f*g*x^2)/d), x], x, Sqrt[c + d*x]], x] /; FreeQ[{F, c, d, e, f, g}, x] &&  !$UseGamma === True

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2296

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_.), x_Symbol] :> Simp[x*(a + b*Log[c*x^n])^p, x] - Dist[b*n*p, In
t[(a + b*Log[c*x^n])^(p - 1), x], x] /; FreeQ[{a, b, c, n}, x] && GtQ[p, 0] && IntegerQ[2*p]

Rule 2299

Int[((a_.) + Log[(c_.)*(x_)^(n_.)]*(b_.))^(p_), x_Symbol] :> Dist[1/(n*c^(1/n)), Subst[Int[E^(x/n)*(a + b*x)^p
, x], x, Log[c*x^n]], x] /; FreeQ[{a, b, c, p}, x] && IntegerQ[1/n]

Rule 2389

Int[((a_.) + Log[(c_.)*((d_) + (e_.)*(x_))^(n_.)]*(b_.))^(p_.), x_Symbol] :> Dist[1/e, Subst[Int[(a + b*Log[c*
x^n])^p, x], x, d + e*x], x] /; FreeQ[{a, b, c, d, e, n, p}, x]

Rubi steps

\begin {align*} \int \sqrt {\log (c (d+e x))} \, dx &=\frac {\operatorname {Subst}\left (\int \sqrt {\log (c x)} \, dx,x,d+e x\right )}{e}\\ &=\frac {(d+e x) \sqrt {\log (c (d+e x))}}{e}-\frac {\operatorname {Subst}\left (\int \frac {1}{\sqrt {\log (c x)}} \, dx,x,d+e x\right )}{2 e}\\ &=\frac {(d+e x) \sqrt {\log (c (d+e x))}}{e}-\frac {\operatorname {Subst}\left (\int \frac {e^x}{\sqrt {x}} \, dx,x,\log (c (d+e x))\right )}{2 c e}\\ &=\frac {(d+e x) \sqrt {\log (c (d+e x))}}{e}-\frac {\operatorname {Subst}\left (\int e^{x^2} \, dx,x,\sqrt {\log (c (d+e x))}\right )}{c e}\\ &=-\frac {\sqrt {\pi } \text {erfi}\left (\sqrt {\log (c (d+e x))}\right )}{2 c e}+\frac {(d+e x) \sqrt {\log (c (d+e x))}}{e}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 50, normalized size = 1.00 \[ \frac {(d+e x) \sqrt {\log (c (d+e x))}}{e}-\frac {\sqrt {\pi } \text {erfi}\left (\sqrt {\log (c (d+e x))}\right )}{2 c e} \]

Antiderivative was successfully verified.

[In]

Integrate[Sqrt[Log[c*(d + e*x)]],x]

[Out]

-1/2*(Sqrt[Pi]*Erfi[Sqrt[Log[c*(d + e*x)]]])/(c*e) + ((d + e*x)*Sqrt[Log[c*(d + e*x)]])/e

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fricas [F(-2)]  time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(c*(e*x+d))^(1/2),x, algorithm="fricas")

[Out]

Exception raised: TypeError >>  Error detected within library code:   integrate: implementation incomplete (co
nstant residues)

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giac [A]  time = 0.24, size = 55, normalized size = 1.10 \[ -\frac {\sqrt {\pi } i \operatorname {erf}\left (-i \sqrt {\log \left (c x e + c d\right )}\right ) e^{\left (-1\right )}}{2 \, c} + \frac {{\left (c x e + c d\right )} e^{\left (-1\right )} \sqrt {\log \left (c x e + c d\right )}}{c} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(c*(e*x+d))^(1/2),x, algorithm="giac")

[Out]

-1/2*sqrt(pi)*i*erf(-i*sqrt(log(c*x*e + c*d)))*e^(-1)/c + (c*x*e + c*d)*e^(-1)*sqrt(log(c*x*e + c*d))/c

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maple [F]  time = 0.19, size = 0, normalized size = 0.00 \[ \int \sqrt {\ln \left (\left (e x +d \right ) c \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(ln((e*x+d)*c)^(1/2),x)

[Out]

int(ln((e*x+d)*c)^(1/2),x)

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maxima [C]  time = 0.62, size = 49, normalized size = 0.98 \[ -\frac {-i \, \sqrt {\pi } \operatorname {erf}\left (i \, \sqrt {\log \left (c e x + c d\right )}\right ) - 2 \, {\left (c e x + c d\right )} \sqrt {\log \left (c e x + c d\right )}}{2 \, c e} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(log(c*(e*x+d))^(1/2),x, algorithm="maxima")

[Out]

-1/2*(-I*sqrt(pi)*erf(I*sqrt(log(c*e*x + c*d))) - 2*(c*e*x + c*d)*sqrt(log(c*e*x + c*d)))/(c*e)

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mupad [B]  time = 0.18, size = 46, normalized size = 0.92 \[ \frac {\sqrt {\ln \left (c\,\left (d+e\,x\right )\right )}\,\left (d+e\,x\right )}{e}+\frac {\sqrt {\pi }\,\mathrm {erf}\left (\sqrt {\ln \left (c\,\left (d+e\,x\right )\right )}\,1{}\mathrm {i}\right )\,1{}\mathrm {i}}{2\,c\,e} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(log(c*(d + e*x))^(1/2),x)

[Out]

(log(c*(d + e*x))^(1/2)*(d + e*x))/e + (pi^(1/2)*erf(log(c*(d + e*x))^(1/2)*1i)*1i)/(2*c*e)

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sympy [A]  time = 2.24, size = 90, normalized size = 1.80 \[ \begin {cases} \tilde {\infty } x & \text {for}\: c = 0 \\x \sqrt {\log {\left (c d \right )}} & \text {for}\: e = 0 \\\frac {\left (\sqrt {- \log {\left (c d + c e x \right )}} \left (c d + c e x\right ) + \frac {\sqrt {\pi } \operatorname {erfc}{\left (\sqrt {- \log {\left (c d + c e x \right )}} \right )}}{2}\right ) \sqrt {\log {\left (c d + c e x \right )}}}{c e \sqrt {- \log {\left (c d + c e x \right )}}} & \text {otherwise} \end {cases} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(ln(c*(e*x+d))**(1/2),x)

[Out]

Piecewise((zoo*x, Eq(c, 0)), (x*sqrt(log(c*d)), Eq(e, 0)), ((sqrt(-log(c*d + c*e*x))*(c*d + c*e*x) + sqrt(pi)*
erfc(sqrt(-log(c*d + c*e*x)))/2)*sqrt(log(c*d + c*e*x))/(c*e*sqrt(-log(c*d + c*e*x))), True))

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